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What makes a 'function' smooth.
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Bill Taylor  
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 More options Oct 2 2002, 8:00 am
Newsgroups: sci.logic, sci.physics, sci.math
From: math...@math.canterbury.ac.nz (Bill Taylor)
Date: Wed, 2 Oct 2002 02:20:26 +0000 (UTC)
Local: Wed, Oct 2 2002 7:50 am
Subject: Re: What makes a 'function' smooth.

Maleki <maleki...@hotmail.com> writes:

|> You misunderstood that "cargo" thing.
|> You misinterpreted their intention and incentives.
|>
|> There are some aspects of humanities that Westerners do
|> not qualify to bother with.

Well don't just leave it there!   Please enlighten us!!

Tell us what WERE the intentions and incentives of the Papuans who set out
the cargo-cult airfields.  I would really like to hear about them.

--------------------------------------------------------------------------- ---
              Bill Taylor          W.Tay...@math.canterbury.ac.nz
--------------------------------------------------------------------------- ---
                       Memes don't exist - pass it on.
--------------------------------------------------------------------------- ---

.


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Maleki  
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 More options Oct 2 2002, 11:03 am
Newsgroups: sci.logic, sci.physics, sci.math
From: Maleki <maleki...@hotmail.com>
Date: Wed, 02 Oct 2002 00:33:38 -0500
Local: Wed, Oct 2 2002 11:03 am
Subject: Re: What makes a 'function' smooth.
On Wed, 2 Oct 2002 02:20:26 +0000 (UTC),
math...@math.canterbury.ac.nz (Bill Taylor) wrote in
<andl5a$it...@cantuc.canterbury.ac.nz> that:

>Maleki <maleki...@hotmail.com> writes:

>|> You misunderstood that "cargo" thing.
>|> You misinterpreted their intention and incentives.
>|>
>|> There are some aspects of humanities that Westerners do
>|> not qualify to bother with.

>Well don't just leave it there!   Please enlighten us!!

>Tell us what WERE the intentions and incentives of the Papuans who set out
>the cargo-cult airfields.  I would really like to hear about them.

I want Green and Kolkor pay money for my answer :) And
I feel like every Western archaeologist's wife should
suck my dick for the one paragraph answer I could give
to their two hundred years of stupidity and confusion
in making such interpretations. And there's more: I'm
not bragging nonsense! Anybody could see the simple
truth of it after reading it.

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Gregory L. Hansen  
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 More options Oct 2 2002, 7:21 pm
Newsgroups: sci.logic, sci.physics, sci.math
From: glhan...@steel.ucs.indiana.edu (Gregory L. Hansen)
Date: Wed, 2 Oct 2002 13:51:32 +0000 (UTC)
Local: Wed, Oct 2 2002 7:21 pm
Subject: Re: What makes a 'function' smooth.
In article <andl5a$it...@cantuc.canterbury.ac.nz>,

Bill Taylor <math...@math.canterbury.ac.nz> wrote:
>Maleki <maleki...@hotmail.com> writes:

>|> You misunderstood that "cargo" thing.
>|> You misinterpreted their intention and incentives.
>|>
>|> There are some aspects of humanities that Westerners do
>|> not qualify to bother with.

>Well don't just leave it there!   Please enlighten us!!

>Tell us what WERE the intentions and incentives of the Papuans who set out
>the cargo-cult airfields.  I would really like to hear about them.

Building the radio huts with sticks for antennas, drilling in military
fashion with sticks for rifles...

--
"A nice adaptation of conditions will make almost any hypothesis agree
with the phenomena.  This will please the imagination but does not advance
our knowledge." -- J. Black, 1803.


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Randy Poe  
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 More options Oct 2 2002, 8:05 pm
Newsgroups: sci.logic, sci.physics, sci.math
From: Randy Poe <r...@nospam.com>
Date: Wed, 02 Oct 2002 10:11:21 -0400
Local: Wed, Oct 2 2002 7:41 pm
Subject: Re: What makes a 'function' smooth.

Maleki wrote:
> On Wed, 2 Oct 2002 02:20:26 +0000 (UTC),
> math...@math.canterbury.ac.nz (Bill Taylor) wrote in
>>Tell us what WERE the intentions and incentives of the Papuans who set out
>>the cargo-cult airfields.  I would really like to hear about them.

> I want Green and Kolkor pay money for my answer :) And
> I feel like every Western archaeologist's wife should
> suck my dick for the one paragraph answer I could give

Interesting. So your basic internal conflict is a hatred
of the west mixed with deep-seated sexual fantasies about
western women. A Freudian could have a field day here.

Refusal to answer noted.

            - Randy


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Uncle Al  
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 More options Oct 2 2002, 8:22 pm
Newsgroups: sci.logic, sci.physics, sci.math
From: Uncle Al <Uncle...@hate.spam.net>
Date: Wed, 02 Oct 2002 14:52:44 GMT
Local: Wed, Oct 2 2002 8:22 pm
Subject: Re: What makes a 'function' smooth.

[snip]

What is the assigned value of the null set?

Cargo cultism is the basis of each and all religions - "Lord, please
change the nature of physical reality for my benefit.  I will worship
you and hurt myself in repayment."  Science is equally simply stated -
mathematically model reality with empirical boundary conditions, then
go with the flow.

Cargo cultism can be accessed by any credulous moron with blood to
bleed.  The Third World is loaded with four billion scrofulous chumps,
and the Second World with another billion.  Science requires a working
brain and significant personal committment.  The First World contains
about a billion sleek and clean folk.  Of those, perhaps only 2%
qualify as lightbringers - and it works.

America = a fantatistically wealthy ruling class, an expansive wealthy
middle class, and a minor well-to-do underclass.  The worst LA,
Chicago, Detroit, Philadelphia, New York... slums have individual
homes, clean running water, sanitation, heat and air conditioning,
Cable TV, public education, public transportation, public
libraries...; subsidized rent, subsidized food, free legal
representation, free medical care...  Compare with a Brazilian favela.

America + god = Mexico or Arabia; a fantastically wealthy ruling
class, a small well-to-do middle class, and a vast ulcerous underclass
wailing to god as they carve their initials in their surviving
children's flesh.  Of course, Muslims literally carve their kids'
flesh - but only the genitalia.  It's God's will.

--
Uncle Al
http://www.mazepath.com/uncleal/
 (Toxic URL! Unsafe for children and most mammals)
"Quis custodiet ipsos custodes?"  The Net!


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Maleki  
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 More options Oct 2 2002, 10:26 pm
Newsgroups: sci.logic, sci.physics, sci.math
From: Maleki <maleki...@hotmail.com>
Date: Wed, 02 Oct 2002 11:56:34 -0500
Local: Wed, Oct 2 2002 10:26 pm
Subject: Re: What makes a 'function' smooth.
On Wed, 02 Oct 2002 14:52:44 GMT, Uncle Al
<Uncle...@hate.spam.net> wrote in
<3D9B0835.50F71...@hate.spam.net> that:

>> I want Green and Kolkor pay money for my answer
>[snip]

>What is the assigned value of the null set?

I want it out of their pockets, not yours. I have other
plans for you :) You'll know better when you first
touch your forehead down in recognition for Allah.

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Edward Green  
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 More options Oct 2 2002, 11:02 pm
Newsgroups: sci.logic, sci.physics, sci.math
From: nullde...@aol.com (Edward Green)
Date: 2 Oct 2002 10:32:48 -0700
Local: Wed, Oct 2 2002 11:02 pm
Subject: Re: What makes a 'function' smooth.

WTF is "two hundred years"?  The cargo cults started after WWII.

The simple truth of the matter is apparently that there is some truth
to the idea that anti-western and in particular anti-western Muslim
males (though I don't know if that includes you) are motivated in part
by sexual envy.  Otherwise your schoolyard sexual boasting is hard to
understand.

So what is your startling alternative theory?  Or is all you have
bragging nonsense?


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Maleki  
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 More options Oct 2 2002, 11:29 pm
Newsgroups: sci.logic, sci.physics, sci.math
From: Maleki <maleki...@hotmail.com>
Date: Wed, 02 Oct 2002 12:59:11 -0500
Local: Wed, Oct 2 2002 11:29 pm
Subject: Re: What makes a 'function' smooth.
On 2 Oct 2002 10:32:48 -0700, nullde...@aol.com (Edward
Green) wrote in
<2a0cceff.0210020932.70876...@posting.google.com> that:

>WTF is "two hundred years"?  The cargo cults started after WWII.

Notion of Cargo Cultism is a sample of a mistake that's
general trend in Westerners. The other sample of that
trend is how Western archaeologists have been
interpreting ornaments and food found in old graves for
the past "two hundred" or so years. Same mistake by
same people for same reason.

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Jan Bielawski  
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 More options Oct 3 2002, 4:53 am
Newsgroups: sci.logic, sci.physics, sci.math
From: j...@nostalghia.com (Jan Bielawski)
Date: 2 Oct 2002 16:23:40 -0700
Local: Thurs, Oct 3 2002 4:53 am
Subject: Re: What makes a 'function' smooth.

Maleki <maleki...@hotmail.com> wrote in message <news:r8cmpucedk4e7fgo44atnscbak23fbehhc@4ax.com>...
> On 2 Oct 2002 10:32:48 -0700, nullde...@aol.com (Edward
> Green) wrote in
> <2a0cceff.0210020932.70876...@posting.google.com> that:

> >WTF is "two hundred years"?  The cargo cults started after WWII.

> Notion of Cargo Cultism is a sample of a mistake that's
> general trend in Westerners. The other sample of that
> trend is how Western archaeologists have been
> interpreting ornaments and food found in old graves for
> the past "two hundred" or so years. Same mistake by
> same people for same reason.

Is there any reason why you keep talking about mistakes but never
explaining them? The suspense is killing me...

    Jan Bielawski


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Ali Khan  
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 More options Oct 3 2002, 11:13 pm
Newsgroups: sci.logic, sci.physics, sci.math
From: "Ali Khan" <alikhan...@btinternet.com>
Date: Thu, 3 Oct 2002 17:41:45 +0000 (UTC)
Local: Thurs, Oct 3 2002 11:11 pm
Subject: Re: What makes a 'function' smooth.

Well, you are right in a way; Sexual envy is a subset of general lifestyle envy, and yes, superficially, I think many people in the 3rd world do envy the western way, but that is not because of the superiority of the western ethos, its merely because of the excellent eloquence and subtlety of its propagandists (or should I say Spin-doctors), and its purchased sterile shine and class (make no mistake, culture and sophistication are almost as readily purchased as a big mac). I dont really think the choking of billions is something to brag about. I myself am Pakistani Muslim, but am also British, and in terms of personal wealth and lifestyle, have no right at all to point a finger at anyone, which is why I am not, I am merely making an observation. Since we are all mathematicians here, I am confident that a flame war will not erupt.

Thanks

Ali


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Edward Green  
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 More options Oct 4 2002, 11:43 am
Newsgroups: sci.logic, sci.physics, sci.math
From: nullde...@aol.com (Edward Green)
Date: 3 Oct 2002 23:13:56 -0700
Local: Fri, Oct 4 2002 11:43 am
Subject: Re: What makes a 'function' smooth.

"Ali Khan" <alikhan...@btinternet.com> wrote in message <news:anhvgm$hoi$1@helle.btinternet.com>...
> Well, you are right in a way; Sexual envy is a subset of general
> lifestyle envy, and yes, superficially, I think many people in the 3rd
> world do envy the western way, but that is not because of the
> superiority of the western ethos, its merely because of the excellent
> eloquence and subtlety of its propagandists (or should I say
> Spin-doctors), and its purchased sterile shine and class (make no
> mistake, culture and sophistication are almost as readily purchased as a
> big mac). I dont really think the choking of billions is something to
> brag about. I myself am Pakistani Muslim, but am also British, and in
> terms of personal wealth and lifestyle, have no right at all to point a
> finger at anyone, which is why I am not, I am merely making an
> observation. Since we are all mathematicians here, I am confident that a
> flame war will not erupt.

Not quite all ... note cross-posting.

One point ... I do not think western propagandists/marketers (same
thing) necessarily spend much time trying to ...

What the heck am I saying!  Check that.  Of course they would want to
instill a longing in the third world for western lifestyles ... growth
market.

Hmm... have to agree with your "culture and sophistication" comment
... or again, at least that's a common marketing ploy.  One reason I
stopped reading "The New Yorker" magazine: I couldn't stand the adds
... they were all aimed at the affluent, and told them that only
_they_ had the taste and refinement to purchase (mostly autos, cloths,
perfumes, etc.) ... which fortunately they also had the money for.
What a coincidence.


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Ali Khan  
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 More options Oct 4 2002, 6:27 pm
Newsgroups: sci.math
From: "Ali Khan" <alikhan...@btinternet.com>
Date: Fri, 4 Oct 2002 12:56:21 +0000 (UTC)
Local: Fri, Oct 4 2002 6:26 pm
Subject: Re: What makes a 'function' smooth.
Sorry about the cross-posting, it was unintentional, I merely clicked the
"reply to group button".

on a semi-tangential point:

The big picture is so confusing, it is best avoided.
The reason I say this is that I honestly do not believe that a rational
person can have a complete and sufficient model for the whole world given
the assumptions that in my opinion a rational person must make, I.e. those
of human equality, and the necessity for minimization of suffering. On the
other hand, smaller scale models and morality guidelines can be established
that extend to say your neighbourhood, and if you are really ambitious, your
country, although even that is very hard.

anyway, this thread is becoming more and more non -mathematical

thanks guys

Regards

Ali

"Edward Green" <nullde...@aol.com> wrote in message

news:2a0cceff.0210032213.449d2422@posting.google.com...
> "Ali Khan" <alikhan...@btinternet.com> wrote in message

<news:anhvgm$hoi$1@helle.btinternet.com>...


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"G.E. Ivey"  
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 More options Oct 5 2002, 4:05 am
Newsgroups: sci.math
From: george.i...@gallaudet.edu ("G.E. Ivey")
Date: Tue, 1 Oct 2002 12:55:25 +0000 (UTC)
Local: Tues, Oct 1 2002 6:25 pm
Subject: Re: What makes a 'function' smooth.
   In many texts you see the phrase "for f a sufficiently smooth
function" meaning "f has as many derivatives as we need".

On 30 Sep 2002, Bryan Reed wrote:


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"G.E. Ivey"  
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 More options Oct 5 2002, 4:05 am
Newsgroups: sci.math
From: george.i...@gallaudet.edu ("G.E. Ivey")
Date: Tue, 1 Oct 2002 12:55:25 +0000 (UTC)
Local: Tues, Oct 1 2002 6:25 pm
Subject: Re: What makes a 'function' smooth.
On 01 Oct 2002, David C. Ullrich wrote:

  The point of that is that "partial derivatives" are NOT true
derivatives.  The derivative of a real valued function of
several variables is its gradient.

  More correctly, its the linear transformation T(x) corresponding to
dot product of the gradient with the vector x.


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kal  
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 More options Oct 5 2002, 4:09 am
Newsgroups: sci.math
From: k_am...@yahoo.com (kal)
Date: Wed, 2 Oct 2002 18:08:15 +0000 (UTC)
Local: Wed, Oct 2 2002 11:38 pm
Subject: Re: What makes a 'function' smooth.

>Building the radio huts with sticks for antennas, drilling in
>military fashion with sticks for rifles...

Whoa! Easy, easy there!

I think it would be a lot of fun to build 'radio huts' and drill in
military fashion with sticks for rifles.  (If you do not intend to
shoot then sticks are just as good as rifles.)

Anyway, this peculiar affliction is common to all humanity and
occurs in all ages.  This is what Samuel Johnson once said about doctors of his day: "Doctors are especially given to mistaking
subsequences for consequences."

We all do something similar in various circumstances.  Madison avenue
thrives on the fact that people often commit similar mistakes.  That
is why we are shown beautiful ladies with alcoholic beverages instead
of belching, pot bellied, foul smelling slobs.

I wonder if God is a 'smooth function'!

--
     "For every credibility gap there is a gullibility fill." -- ?


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Discussion subject changed to "gradients (was Re: What makes a 'function' smooth.)" by Kevin Foltinek
Kevin Foltinek  
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 More options Oct 5 2002, 5:25 am
Newsgroups: sci.math
From: Kevin Foltinek <folti...@math.utexas.edu>
Date: 04 Oct 2002 18:51:43 -0500
Local: Sat, Oct 5 2002 5:21 am
Subject: gradients (was Re: What makes a 'function' smooth.)

george.i...@gallaudet.edu ("G.E. Ivey") writes:
> The derivative of a real valued function of several variables is its
> gradient.

>   More correctly, its the linear transformation T(x) corresponding to
> dot product of the gradient with the vector x.

Your first statement is rather bad, your second statement is rather
bad for different reasons (is the linear transformation T or T(x)?)
but is still not quite correct.

The truly correct statement is the following:
  On a Riemannian manifold (e.g., R^n with the usual dot product), the
  gradient of a function at x is defined by
    grad f(x) := G^{-1}(df(x))
  where G : T_xM -> T*_xM is the vector space isomorphism defined by
    G(v)(w) := g(v,w)
  and g is the inner product.
For the non-differential geometers, this is the same as
    grad f(x) := transpose(Df(x))
(remember that the transpose is an operation defined in terms of the
dot product).

You'll note that the derivative Df(x)=df(x) is defined without
reference to the metric.

Kevin.


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Lee Rudolph  
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 More options Oct 5 2002, 5:22 pm
Newsgroups: sci.math
From: lrudo...@panix.com (Lee Rudolph)
Date: 5 Oct 2002 07:52:58 -0400
Local: Sat, Oct 5 2002 5:22 pm
Subject: Re: gradients (was Re: What makes a 'function' smooth.)

Kevin Foltinek <folti...@math.utexas.edu> writes:
>The truly correct statement is the following:
>  On a Riemannian manifold (e.g., R^n with the usual dot product), the
>  gradient of a function at x is defined by
>    grad f(x) := G^{-1}(df(x))
>  where G : T_xM -> T*_xM is the vector space isomorphism defined by
>    G(v)(w) := g(v,w)
>  and g is the inner product.
>For the non-differential geometers, this is the same as
>    grad f(x) := transpose(Df(x))
>(remember that the transpose is an operation defined in terms of the
>dot product).

>You'll note that the derivative Df(x)=df(x) is defined without
>reference to the metric.

A nice way to picture this (well, I like it), inspired (for me) by
a remark of Edward Nelson's somewhere or other, is as follows.

On an n-manifold M (e.g., R^n, not yet equipped with a dot product),
given a function f:M->R, we can look at the level sets M_t = f^{-1}(t).
Suppose x is a point of M_0, that M_0 is an (n-1)-manifold near x,
and that M_t is an (n-1)-manifold near x for t near 0.  Then the
partition of a coordinate neighborhood N of x in M into the level
sets N_t = N\intersect M_t looks, to first order, like the partition
of the tangent n-space V of M at x (which is of course just R^n again
if M is R^n) into parallel "equally spaced" hyperplanes induced by some
linear functional on V.  That linear functional is df(x).

This is the "manifoldization" of an easy, but rarely discussed,
geometric development of covectors in any affine space that is
completely dual to the equally easy, and totally standard, geometric
development of vectors.  Namely, a (non-zero) geometric vector is an
equivalence class of oriented line segments, where the segment from
A to B is equivalent to the segment from A' to B' if and only if
the line through A and B is parallel to the line through A' and B'
and the line through A and A' is parallel to the line through B
and B'; dually, a (non-zero) geometric covector is an equivalence
class of "oriented scales" (ordered pairs of distinct parallel
hyperplanes), where the scale from (hyperplane) P to (hyperplane)
Q is equivalent to the scale from P' to Q' if and only if ...
you do it.  Geometric vectors and geometric covectors are paired
by the (geometric) operation of "measuring an oriented segment
with an oriented scale".  A positive definite inner product imposes
an isomorphism between the two spaces.  Back in the manifold,
that's where the gradient comes from.

Lee Rudolph


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Discussion subject changed to "What makes a 'function' smooth." by V.Gopal
V.Gopal  
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 More options Oct 5 2002, 9:42 pm
Newsgroups: sci.logic, sci.physics, sci.math
From: vgopa...@rediffmail.com (V.Gopal)
Date: 5 Oct 2002 09:12:47 -0700
Local: Sat, Oct 5 2002 9:42 pm
Subject: Re: What makes a 'function' smooth.
nullde...@aol.com (Edward Green) wrote in message <news:2a0cceff.0210011438.51a5b77@posting.google.com>...
> vgopa...@rediffmail.com (V.Gopal) wrote in message <news:38af3945.0209301116.77a62c6c@posting.google.com>...

> ...

> > A smooth function/activity has to be understood by psychophysical
> > parallelism, intellectual sympathy, introspection and meditation.
> > Everything in nature is smooth. No language is smooth. Nature is meant
> > to enhance our capacity for sympathy, introspection and meditation. We
> > can realize the exictence of God only by understanding 'The smooth'.

> Enough said. ;)

Not yet. Let me add one more - Any activity that proceeds on
self-reference (if it is possible to proceed at all) then that
activity is smooth.

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V.Gopal  
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 More options Oct 6 2002, 10:37 am
Newsgroups: sci.math
From: vgopa...@rediffmail.com (V.Gopal)
Date: 5 Oct 2002 22:07:09 -0700
Local: Sun, Oct 6 2002 10:37 am
Subject: Re: What makes a 'function' smooth.

God is not a 'smooth function'. HE FUNCTIONS smoothly and does not
perform miracles (deism). His methods involve self-reference,
continuous change in reference and continuous FORGETTING of the past.
From human point of view everything HE does is intelligible - we can
justify events but cannot foresee (unless by nature the event is
statistically predictable with zero error.)  We cannot describe his
methods although we can justify the events. If anybody survives after
the ship has sunk, he (the survivor) would definitely tell how it
could have been saved - with so much of confidence that it would
appear as if he had foreen the disaster!

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Discussion subject changed to "gradients (was Re: What makes a 'function' smooth.)" by Shmuel (Seymour J.) Metz
Shmuel (Seymour J.) Metz  
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 More options Oct 7 2002, 10:23 pm
Newsgroups: sci.math
From: "Shmuel (Seymour J.) Metz" <spamt...@library.lspace.org.invalid>
Date: Mon, 07 Oct 2002 11:35:45 -0400
Local: Mon, Oct 7 2002 9:05 pm
Subject: Re: gradients (was Re: What makes a 'function' smooth.)
In <anmjqq$71...@panix5.panix.com>, on 10/05/2002
   at 07:52 AM, lrudo...@panix.com (Lee Rudolph) said:

>On an n-manifold M (e.g., R^n, not yet equipped with a dot product),
>given a function f:M->R, we can look at the level sets M_t =
>f^{-1}(t). Suppose x is a point of M_0, that M_0 is an (n-1)-manifold
>near x, and that M_t is an (n-1)-manifold near x for t near 0.  Then
>the partition of a coordinate neighborhood N of x in M into the level
>sets N_t = N\intersect M_t looks, to first order, like the partition
>of the tangent n-space V of M at x (which is of course just R^n again
>if M is R^n) into parallel "equally spaced" hyperplanes induced by
>some linear functional on V.  That linear functional is df(x).

Without a metric, how do you map the tamgent space of M_t at t into
the tangent space of M at x? Even with a metric, how do you do it,
without assuming zero curvature?

The conventional approach of defining df(x) as an equivalence class of
functions is simple and doesn't depend on a metric.

--
     Shmuel (Seymour J.) Metz, SysProg and JOAT
     Atid/2, Team OS/2, Team PL/I

Any unsolicited commercial junk E-mail will be subject to legal
action.  I reserve the right to publicly post or ridicule any
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I mangled my E-mail address to foil automated spammers; reply to
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Discussion subject changed to "What makes a 'function' smooth." by puppet_s...@hotmail.com
puppet_sock  
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 More options Oct 8 2002, 12:00 am
Newsgroups: sci.logic, sci.physics, sci.math
From: puppet_s...@hotmail.com
Date: 7 Oct 2002 11:30:30 -0700
Local: Tues, Oct 8 2002 12:00 am
Subject: Re: What makes a 'function' smooth.

Maleki <maleki...@hotmail.com> wrote in message <news:r8cmpucedk4e7fgo44atnscbak23fbehhc@4ax.com>...
> Notion of Cargo Cultism is a sample of a mistake that's
> general trend in Westerners. The other sample of that
> trend is how Western archaeologists have been
> interpreting ornaments and food found in old graves for
> the past "two hundred" or so years. Same mistake by
> same people for same reason.

Anybody who has been making the same mistake for 200 years
would have to be a much older person.

Actually, Maleki, you are a grossly racist pile of smeg.
Socks


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Discussion subject changed to "gradients (was Re: What makes a 'function' smooth.)" by Kevin Foltinek
Kevin Foltinek  
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 More options Oct 8 2002, 3:55 am
Newsgroups: sci.math
From: Kevin Foltinek <folti...@math.utexas.edu>
Date: 07 Oct 2002 17:19:33 -0500
Local: Tues, Oct 8 2002 3:49 am
Subject: Re: gradients (was Re: What makes a 'function' smooth.)
"Shmuel (Seymour J.) Metz" <spamt...@library.lspace.org.invalid> writes:

It's not a mapping of tangent spaces into tangent spaces; it's a
mapping of submanifolds of M into submanifolds of R^n.  The only
tangent space under consideration is the tangent space at x.  A
coordinate chart around x maps N to R^n; it may as well map N to T_xM
(which is vector-space isomorphic to R^n).

In the coordinate neighbourhood N, suppose x is at the origin (i.e., x
is mapped to the origin via the coordinate chart); without loss of
generality,
  f^{-1}(0) = {(x1,...,x[n-1],0)} ,
and by the implicit function theorem,
  f^{-1}(t) = {(x1,...,x[n-1],g_t(x1,...,x[n-1]))} .
In other words, each N_t is the graph of a function g_t:R^{n-1}->R .

If D_nf(0) is non-zero, then it is non-zero in a neighbourhood, and
we can thus assume (by making a second-order change of the x[n]
coordinate) that g_t(0,...,0) = D_nf(0) t .

Finally, we can make another second-order change of coordinates such
that g_t(x1,...,x[n-1]) = D_nf(0) t .

I've left out some details, of course.

> The conventional approach of defining df(x) as an equivalence class of
> functions is simple

as is the other conventional approach of defining df(x) as a linear
mapping of equivalence classes of curves (tangent vectors), and maybe
a few other conventional approaches. :-)

The picture presented by Lee is, I think, useful not so much in
understanding df (probably because of the complexity of filling in all
the details that I left out), but in understanding the linear algebra
of a vector space and its dual.

Kevin.


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